Files
ykxmz/_build/check_tunnel_state.sh
xmz7891 bcb089eded 看门狗:连接数掉到 1 就立刻重启,不等攒够 3 次
排查公网间歇 530 时发现的:
  watchdog 日志显示「公网不通(HTTP 530,ha_connections=1)」
  —— 出问题那段时间隧道**只剩 1 条连接**。

原来 watchdog 只把 CONNS == 0 算"零连接",
CONNS == 1 不当回事。但实测**只剩一条连接时跨机房回源就会失败**
(请求落 SEA,隧道只剩 LAX 一条)。

改法:
  * CONNS <= 1 都计入降级计数
  * 公网不通 **且** 连接数已在危险区 = 确认的故障(不是短抖动)
    -> 立刻重启,不等 3 次

每次检查间隔 20 秒,等 3 次就是白断 40 秒。现在能省下来。

实测:改完公网 15/15 = 100%,连接数 4 条。

顺带说明 watchdog 是怎么跑的:
  systemd timer(lanremote-watchdog.timer),每 20 秒调一次
  watchdog.service。之前查"服务是 inactive"一度以为它没在跑,
  其实是 timer 触发型的 —— oneshot 服务跑完就是 inactive,正常。
2026-10-07 10:00:50 +08:00

67 lines
2.5 KiB
Bash

#!/bin/bash
# 公网间歇 530 —— 查隧道当前真实状态
set -u
echo " relay=$(systemctl is-active lanremote-relay) tunnel=$(systemctl is-active lanremote-tunnel)"
echo " 隧道连接数: $(curl -s --max-time 5 http://127.0.0.1:20241/metrics 2>/dev/null | grep '^cloudflared_tunnel_ha_connections' | awk '{print $2}')"
echo
echo "════════ watchdog 最近 15 行 ════════"
tail -15 /root/lanremote-relay/watchdog.log 2>/dev/null | sed 's/^/ /'
echo
echo "════════ watchdog 怎么被调起来的 ════════"
echo " 服务: $(systemctl is-active lanremote-watchdog 2>&1)"
crontab -l 2>/dev/null | grep -i watch | sed 's/^/ cron: /'
systemctl list-timers --all 2>/dev/null | grep -i watch | sed 's/^/ timer: /'
echo
echo "════════ 隧道最近的重连频率(1500 行内)════════"
for kw in 'Registered tunnel connection' 'Lost connection' 'Retrying connection' 'i/o timeout' 'context deadline'; do
n=$(tail -1500 /root/lanremote-relay/tunnel.log 2>/dev/null | grep -c "$kw")
printf " %-34s %s 次\n" "$kw" "$n"
done
echo
echo "════════ 出口 IP 可达性 ════════"
python3 - <<'PY'
import socket, time
ips = ["198.41.192.107", "198.41.200.43", "198.41.192.77",
"198.41.200.113", "198.41.192.227", "198.41.200.193",
"198.41.192.37", "198.41.200.63"]
ok = 0
for ip in ips:
s = socket.socket(); s.settimeout(3)
t = time.perf_counter()
try:
s.connect((ip, 7844))
print(" %-16s %4.0f ms" % (ip, (time.perf_counter()-t)*1000)); ok += 1
except OSError:
print(" %-16s 不通" % ip)
finally:
s.close()
print(" => %d/%d 可达" % (ok, len(ips)))
PY
echo
echo "════════ 公网连打 12 次 ════════"
ok=0
for i in $(seq 1 12); do
c=$(curl -s -o /dev/null -w '%{http_code}' --max-time 15 \
-H 'User-Agent: LanRemote/1.4.0' https://relay.xxmxxs.top/v1/health)
[ "$c" = "200" ] && ok=$((ok+1))
printf " %2d: %s\n" "$i" "$c"
sleep 1
done
echo " 可用 $ok/12"
echo
echo "════════ 本机 relay(排除源站问题)════════"
for i in 1 2 3; do
printf " %d: HTTP %s\n" "$i" "$(curl -s -o /dev/null -w '%{http_code}' --max-time 8 http://127.0.0.1:8080/v1/health)"
done
echo
echo "════════ 网络质量 ════════"
ping -c 10 -W 2 1.1.1.1 2>/dev/null | tail -2 | sed 's/^/ /'