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ykxmz/_tests/test_apk_contents.py
T
xmz7891 5e769928f9 1.6.0:重写 README,面向老师 / 电教 / 开发者 / 普通用户
README
- 原来的 README 是开发者视角(在解释我为什么没做某功能),
  而且通篇 AI 腔。这次按用户视角重写,讲怎么用。
- 开头就分流:老师 / 电教 / 开发者 / 普通用户,各看各的
- 定位改成教室电脑手表遥控,主场景是老师上课管教室那台电脑
- 加了电教专用一节:机房同传部署、脚本批量推、网络规划、权限收口
- 加了开发者一节:三端怎么编译、怎么跑测试、怎么打包
- 加了通信协议一节
- 常见问题、排错顺序、错误对照表都补全

版本号
- 1.5.0 -> 1.6.0(versionCode 107)
- 顺手写了通用的版本升级脚本 _build/bump_version_generic.py,
  以后升版本一条命令就行,不用手改十几个文件
2026-10-06 20:20:11 +08:00

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# -*- coding: utf-8 -*-
"""检查手表 APK 是否真的把「遥控诊断」合并进去了。
合并前是两个 APK(手表端 + 独立的遥控诊断 App)。
合并后只需要一个:主程序里有「设备诊断」按钮。
这里从 APK 的 dex 和清单里核实,而不是只信源码。
"""
from __future__ import annotations
import re
import subprocess
import sys
import tempfile
import zipfile
from pathlib import Path
ROOT = Path(__file__).resolve().parent.parent
# 别写死版本号 —— 一升级就坏(这坑踩过好几回了)。
# 直接扫 dist 里最新的手表 APK。
def _latest_apk() -> Path:
candidates = sorted(
(ROOT / "dist").glob("*watch*.apk"),
key=lambda p: p.stat().st_mtime, reverse=True)
return candidates[0] if candidates else \
ROOT / "dist" / "ykxmz-watch-1.6.0.apk"
APK = _latest_apk()
DIAG_APK = ROOT / "dist" / "LanRemote-Diag-1.1.0.apk"
AAPT = (Path(r"C:\Users\shu\Desktop\deepseekagent\starklink\toolchain")
/ "android-sdk" / "build-tools" / "34.0.0" / "aapt.exe")
PASSED = 0
FAILED = 0
def check(name: str, ok: bool, detail: str = "") -> None:
global PASSED, FAILED
if ok:
PASSED += 1
print(f" [PASS] {name}")
else:
FAILED += 1
print(f" [FAIL] {name} {detail}")
def main() -> int:
print("=" * 68)
print("一、手表 APK 里有没有内置诊断")
print("=" * 68)
if not APK.is_file():
print(f" 找不到 {APK}")
print(" 请先运行 android\\build_apk.ps1")
return 1
with zipfile.ZipFile(APK) as archive:
dex = archive.read("classes.dex")
names = {item.decode() for item in
re.findall(rb"Lcom/lanremote/[A-Za-z0-9_/]+;", dex)}
print(f" dex 中的类: {len(names)} 个")
check("APK 里有 Diagnostics 类(诊断逻辑已内置)",
"Lcom/lanremote/watch/Diagnostics;" in names,
str(sorted(names)))
check("APK 里有 DiscoveryCore(诊断与主程序共用同一份发现实现)",
"Lcom/lanremote/watch/DiscoveryCore;" in names)
check("APK 里有 MainActivity", "Lcom/lanremote/watch/MainActivity;" in names)
# 注意:不能用 "diag" 做子串判断 —— Diagnostics 里也含 diag。
# 要查的是旧的独立包名 com/lanremote/diag/。
legacy = [n for n in names if n.startswith("Lcom/lanremote/diag/")]
check("不含旧的独立诊断包 com.lanremote.diag",
not legacy, str(legacy))
print()
print("=" * 68)
print("二、清单权限(诊断读 WiFi 名称需要定位权限)")
print("=" * 68)
# aapt 不认中文路径,先拷到纯 ASCII 路径
with tempfile.TemporaryDirectory() as tmp:
simple = Path(tmp) / "watch.apk"
simple.write_bytes(APK.read_bytes())
try:
proc = subprocess.run(
[str(AAPT), "dump", "badging", str(simple)],
capture_output=True, timeout=60)
badging = proc.stdout.decode("utf-8", errors="replace")
except Exception as exc: # noqa: BLE001
badging = ""
print(f" aapt 调用失败: {exc}")
if badging:
for permission, why in (
("android.permission.ACCESS_FINE_LOCATION", "读 WiFi 名称"),
("android.permission.INTERNET", "网络通信"),
("android.permission.CHANGE_WIFI_MULTICAST_STATE", "UDP 广播"),
):
check(f"声明了 {permission.split('.')[-1]}({why})",
permission in badging)
check("没有申请定位以外的敏感权限",
"READ_CONTACTS" not in badging
and "READ_SMS" not in badging
and "CAMERA" not in badging
and "RECORD_AUDIO" not in badging)
else:
check("能读取 APK 清单", False, "aapt 没有输出")
print()
print("=" * 68)
print("三、构建脚本不再依赖独立诊断 APK")
print("=" * 68)
package = (ROOT / "_build" / "package.py").read_text(encoding="utf-8")
check("package.py 不再要求 Diag APK",
"DIAG_APK" not in package, "仍引用 DIAG_APK")
check("package.py 说明里写明诊断已合并",
"合并" in package)
src = (ROOT / "android" / "src" / "com" / "lanremote" / "watch"
/ "MainActivity.java").read_text(encoding="utf-8")
# 用户要求:"安卓端中转设置下面,把那个设备诊断给删了,
# 换成输入配对码,输入对应配对码就可以连接对应电脑"
# 所以这里反过来断言:不该再有设备诊断入口,而是配对码输入。
import re as _re
code = _re.sub(r"//[^\n]*", "", src)
check("主界面不再有「设备诊断」入口", "设备诊断" not in code)
check("主界面不再调用 Diagnostics.build",
"Diagnostics.build(" not in code)
check("主界面不再调用 Diagnostics.manualTest",
"Diagnostics.manualTest(" not in code)
check("换成了「输入配对码连接」入口",
'bigButton("输入配对码连接"' in code)
check("配对码连接走中转(connectByCode)",
"private void connectByCode(" in code)
print()
print("=" * 68)
print(f"通过 {PASSED} 项,失败 {FAILED} 项")
print("=" * 68)
return 1 if FAILED else 0
if __name__ == "__main__":
sys.exit(main())